4v=14v^2=48

Solution for 4v=14v^2=48 equation:

4v=14v^2=48

We move all terms to the left:

4v-(14v^2)=0

determiningTheFunctionDomain
-14v^2+4v=0

a = -14; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-14)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-14}=\frac{-8}{-28}
=2/7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-14}=\frac{0}{-28}
=0
$